5n^2+11n-4830=0

Solution for 5n^2+11n-4830=0 equation:

5n^2+11n-4830=0

a = 5; b = 11; c = -4830;
Δ = b2-4ac
Δ = 112-4·5·(-4830)
Δ = 96721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{96721}=311$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-311}{2*5}=\frac{-322}{10}
=-32+1/5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+311}{2*5}=\frac{300}{10}
=30
$